a question regarding torque in a magnetism setting?

Question

so i know IABsintheta = Tau is going to come into play in the problem, but i dont know exactly how to go about doing this... if someone could walk me through that would be great.http://session.masteringphysics.com/problemAsset/1...What is the magnitude of the torque on the circular current loop in the figure? What is the loop's equilibrium position? Pick one of the following when the loop is rotated by 90^circ around vertical axiswhen the loop is rotated by 90^circ around horizontal axis directed into the pagewhen the loop is rotated by 90^circ around horizontal axis directed to the rightcurrent position

Hermina Ferry · Accepted Answer

Magnetic moment : m = I / A = 0.2/[π(2x10-³)²] = 1.59x10^-4 A/m²Amperes’ law for left current-carrying conductor yields formulafor magnetic flux density: B = μI / 2πr = (4πx10^-7)2 / 2π(0.02) = 10^-5 TTorque: T = mxB = mBsinφ = mB = (1.59x10^-4)(10^-5) = 1.59x10^-9 N mBy the Lorentz force law we know that the forcemust be perpendicular to both current directionand magnetic field direction. Using right hand rule: the force cause 90 degreerotation w.r.t horizontal axis.

Hermina Ferry · Answer

First find the magnetic dipole moment of the loop:= IA = I(pi)r^2 = 0.2(pi)(0.002/2)^2 = 6.28 x 10^-7Then find the magnetic field strength (B):B=(mu_0)I/(2(pi)d = (4(pi) x 10 ^ -7 2 / (2(pi)*0.02) = 2 x 10 ^ -5We know that the wire and the loop are perpendicular to each other making 90 degreestorque =  x B = (mu)B sin(angle) = (6.28 x 10^-7)(2 x 10 ^ -5) sin(90) = 1.2566 x 10 ^ -11Be careful. Mastering Physics told me my answer was wrong with this; They wanted 1.3 x 10 ^ -11 Nm

Jakob Littel

a question regarding torque in a magnetism setting?

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