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A rod is bent into an L shape and attached at one point to a pivot. (Figure 1) The rod sits on a frictionless?

A rod is bent into an L shape and attached at one point to a pivot (see Figure 1). The rod rests on a frictionless table, and the diagram is viewed from above. For this problem, gravity can be ignored. Three forces are applied to the rod at different points and angles: F₁, F₂, and F₃. The dimensions of the bent rod are given in centimeters in the figure, but the answers should be provided in SI units (kilograms, meters, seconds).

Part A: If F₃ = 0 and F₁ = 12 N, what must the magnitude of F₂ be for the rod to achieve rotational equilibrium? I have calculated F₂, and it is correct: F₂ = 4.5 N.

Part B: If the L-shaped rod has a moment of inertia I = 9 kg·m², F₁ = 12 N, F₂ = 27 N, and F₃ = 0, how long will it take for the object to rotate through 45° (π/4 radians)? Please express the time t in seconds. Assume that as the object begins to move, each force maintains its initial angle relative to the object.

Part C: Now consider the scenario where F₁ = 12 N and F₂ = 0, but a force with a nonzero magnitude, F₃, is acting on the rod. What must the magnitude of F₃ be to achieve equilibrium? Provide a numerical answer in newtons, to two significant figures. F₃ =

Please express the time in seconds to two significant figures.

1 Answers

A
Anonymous

Jan 11, 2025

B) τ = 12N3cm - 27N8cm = -180 N·cm = -1.8 N·m

But also τ = Iα, so

α = -1.8N·m / 9kg·m² = -0.2 rad/s²

Θ = ½αt²

π/4 rads = ½ 0.2rad/s² t² → t = 2.8 s

C) 12N 3cm = F3 sin30 * 8cm

F3 = 9.0 N

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