A series RLC circuit has a 200 kHz resonance frequency.?
What will the new resonance frequency be if the capacitance in a series RLC circuit is doubled, given that the original resonance frequency is 200 kHz?
1 Answers
Feb 09, 2025
F'r / Fr = [1/2pi sqrt L2C] / [1/2pi sqrt LC]
F'r/Fr = 2pi sqrt LC / [(2pi) (sqrt2)(sqrt LC)]
F'r = Fr(1/sqrt 2)
F'r = (200,000 Hz)/(sqrt 2) = 141,421 Hz
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