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Jakob Littel

Feb 20, 2025

A series RLC circuit has a 200 kHz resonance frequency.?

What is the resonance frequency if the capacitor value is doubled?

1 Answers

H
Hermina Ferry

Feb 20, 2025

F'r / Fr = [1/2pi sqrt L2C] / [1/2pi sqrt LC]F'r/Fr = 2pi sqrt LC / [(2pi) (sqrt2)(sqrt LC)] F'r = Fr(1/sqrt 2)F'r = (200,000 Hz)/(sqrt 2) = 141,421 Hz... Show More

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