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Jakob Littel

Feb 20, 2025

A roller coaster moves 200 ft horizontally, then rises 135 ft at an angle of 30.0° above the horizontal. ?

Next, it travels 135 ft at an angle of 40.0° below the horizontal. Use graphical techniques to find the roller coaster’s displacement from its starting point at the end of this movement
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Hermina Ferry

Feb 20, 2025

Draw a picture: http://i279.photobucket.com/albums/kk154/mwettergr…x_tot = 200 + [135cos(30°)] + [135cos(-40°)] x_tot = 420.3294293 fty_tot = [135sin(30°)] + [135sin(-40°)]y_tot = -19.27632731 ftDisplacement = √(x² + y²)Displacement = √[(420.3294293)² + (-19.27632731)²] Displacement = 420.771204 ftDisplacement = 421 fttanθ = (y / x)tanθ = (-19.27632731 / 420.3294293)θ = arctan (-0.0458600468)θ = -2.625747386°θ = -2.63°Displacement = 421 ft at 2.63° below the horizontal.... Show More
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