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Kelsie Sawayn

Feb 20, 2025

A 1.50m -long, 550g rope pulls a 7.00kg block of ice across a horizontal, frictionless surface. Physics Help?

A 1.50m long, 550g rope pulls a 7.00kg block of ice across a horizontal, frictionless surface. The block accelerates at 2.20m/s2 . How much force pulls forward on (a) the ice, (b) the rope?
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Madie Hilpert

Feb 20, 2025

The ice accelerates @ 2.2m/s^2. It has a mass of 7 kg. F = maF = 7 kg x 2.2 m/s^2 = 15.4 N.The ice / rope "system" has a mass of 7.55 kg. It is also accelerating at a rate of 2.2 m/s^2.F = 7.55 kg x 2.2 m/s^2 = 16.61 N... Show More
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M
Madie Hilpert

Feb 20, 2025

solution;mass of rope m=550g=0.55mass of block mb =7 kg acceleration produced byblock a=2.2m/s^2 now according to the formulaf=ma=7*2.2=15.4N and, acceleration produced by rope means acceleration produced by block;f=ma =[0.55+7]*2.2=16.61NHENCE 15.4N force pulls forward the ice and 16.61N force to the rope... Show More
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