which compund has the greatest percent composition by mass of sulfur…BaS, Cas,Mgs, or SrS?

Question

Prof. Vaughn Howell · Accepted Answer

Tom is correct in his method but he adds a couple of unnecessary steps. You only need consider atomic O and atomic S (not the compounds), so to determine the number of moles you need only divide by the atomic weight (16 for O and 32 for S) and not the molecular weights. When you take the mole ratio, you will find that there are 1.5 O for every 1 S and you easily get the S2O3 empirical formula. You cannot get the molecular formula from this problem (and there is no need to use the molecular forms of O and S in his final step). The answer is S2O3

Prof. Vaughn Howell · Answer

MgS. Mg is the lightest of all of the 2A elements you listed. In MgS, it is ~57% mass S. In BaS, the heaviest 2A element you listed, it is ~19% S. The way to determine this is by dividing the molar mass of sulfur by the molar mass of the compound and multiplying by 100. For MgS, it would be [32.0/(24.3+32.0)]*100=~56.8% mass sulfur.

Prof. Vaughn Howell · Answer

Look at a periodic tableall of these have one Sso the one with the lightest 'other part'will have the highest percent of Sand Mg is the lightest of the choices so it's MgSWhen you get a good response, please consider giving a best answer.This is the only reward we get.

Lori Robel

which compund has the greatest percent composition by mass of sulfur…BaS, Cas,Mgs, or SrS?

3 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions