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Kelsie Sawayn

Feb 20, 2025

A Cessna aircraft has a lift-off speed of 120 km/h.?

A Cessna aircraft has a lift-off speed of 120 km/h.(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 220 m? m/s2 (b) How long does it take the aircraft to become airborne? s

3 Answers

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Hermina Ferry

Feb 20, 2025

(a) 2ad = Vf^2 - Vi^2 a = (Vf^2 - Vi^2)/2d Convert 120 km/hr to m/s: (120 km/hr)(1000m/1km)(1hr/3600sec) = 33.33 m/sec a = [(33.33 m/s)^2 - 0^2]/[2(220m)] a = 2.52 m/s^2 answer(b) t = (Vf - Vi)/a t = (33.33 m/sec - 0)/2.52 m/sec^2 t = 13.2 sec answerHope this helps. teddy boy... Show More
H
Hermina Ferry

Feb 20, 2025

v2 = u2 + 2as. whereu = 0 (initial velocity = 0)v = 120 ( final velocity is the lift of speed)s = 220 (take off run)120^2 = 440aa = 32.7m/s2... Show More

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