Prof. Mozelle Willms
Jan 10, 2025
A Cessna aircraft has a lift-off speed of 120 km/h.?
A Cessna aircraft has a lift-off speed of 120 km/h.
(a) What is the minimum constant acceleration required for the aircraft to become airborne after a takeoff run of 220 meters?
(b) How long does it take for the aircraft to become airborne?
3 Answers
Jan 14, 2025
(a) 2ad = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/2d Convert 120 km/hr to m/s: (120 km/hr)(1000m/1km)(1hr/3600sec) = 33.33 m/sec a = [(33.33 m/s)^2 - 0^2]/[2(220m)] a = 2.52 m/s^2 answer(b) t = (Vf - Vi)/a
t = (33.33 m/sec - 0)/2.52 m/sec^2 t = 13.2 sec answerHope this helps.
teddy boy
v2 = u2 + 2as.
where
u = 0 (initial velocity = 0)
v = 120 ( final velocity is the lift of speed)
s = 220 (take off run)
120^2 = 440a
a = 32.7m/s2
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