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Kelsie Sawayn

Feb 20, 2025

A heat engine does 15 J of work per cycle while exhausting 35 J of waste heat.?

A heat engine does 15 J of work per cycle while exhausting 35 J of waste heat.What is the engine's thermal efficiency?(answer in %)
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3 Answers

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Hermina Ferry

Feb 20, 2025

(15/50) multiplied with 100. 30% efficient. Energy utilized/ total energy * 100... Show More
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H
Hermina Ferry

Feb 20, 2025

total potential, clever and wasted, is 15+32 = 47J. We assume there are actually not the different losses, this being Physics, so as that's comparable to the enter potential. Divide 15/40 seven to get performance.... Show More
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Hermina Ferry

Feb 20, 2025

for Carnot engines, there's a couple of useful equationslike W = Qh - Qcand e = W / Qhwhere (in this case):Qh is the heat absorbed by the engineQc is the heat given off the enginee is efficiency, what we're looking for.for this problem, we're given "35 J of waste heat", which is Qcso with math magic (using the formulas above) we get the following formula:e = W / (W + Qc)in your case: 15 / (15 + 35)which agrees with the guy above, 30%... Show More
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