Britney Roob
Dec 19, 2024
A heat engine does 15 J of work per cycle while exhausting 35 J of waste heat.?
A heat engine performs 15 J of work per cycle while exhausting 35 J of waste heat. What is the thermal efficiency of the engine? Please provide your answer as a percentage.
3 Answers
Jan 15, 2025
(15/50) multiplied with 100. 30% efficient. Energy utilized/ total energy * 100
total potential, clever and wasted, is 15+32 = 47J. We assume there are actually not the different losses, this being Physics, so as that's comparable to the enter potential. Divide 15/40 seven to get performance.
for Carnot engines, there's a couple of useful equations
like W = Qh - Qc
and e = W / Qh
where (in this case):
Qh is the heat absorbed by the engine
Qc is the heat given off the engine
e is efficiency, what we're looking for.
for this problem, we're given "35 J of waste heat", which is Qc
so with math magic (using the formulas above) we get the following formula:
e = W / (W + Qc)
in your case: 15 / (15 + 35)
which agrees with the guy above, 30%
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