Actually, the real answer is: because it happens to be.When we find “equivalencies”, we normally have a conversion factor (a.k.a. a “constant”).In Newtonian gravity, using international units (kg, metres and Newtons) we write: F = G * M * m / d^2where G is called the “Gravitational constant”; its purpose is to make the units match up.G = 6.674*10^-11 N m^2 / kg^2It’s purpose is to convert the kilograms of the mass and the metres of the distance, in units of force (Newtons).Newton himself would have used “slugs” as unit of mass (he invented the name of the unit as a representation of the “sluggishness” caused by inertia), feet as distance and pounds as the unit of force.Thus, his conversion factor would have had a different value and its units would have been “lb* ft^2 / slug^2”When Einstein calculated the full series of the energy contained in a moving object, he found an infinite series that looks like:E = m + (m/2)v^2 + (3m/8)v^4 + …The second term (1/2)mv^2 is the one we call “kinetic energy” in Newtonian physics.Then Einstein does strange things to turn the infinite series into a manageable equation using tensors (don’t ask me, it is beyond vector calculus) and ends up showing that if you use the proper units, then the conversion factor happens to be the speed of light.For example, an intermediate result is that the total apparent energy (the sum of the infinite series), once differentiated, follows the Lorentz transformation (which had been determined separately earlier). This is the result that is misinterpreted as: the mass increases as the speed approaches the speed of light. It is not the mass that increases, but the total energy content of the moving object.Einstein figured out the energy content in some basic unit (he used the dyne) and, as long as he used a speed in cm/s, when he allowed the speed (v) to approach zero, the conversion factor happened to be the speed of light squared (around 9*10^20 cm^2 / s^2).With modern units, we sayE = m c^2where the energy is expressed in Joules (equivalent to 1 N m)the mass is in kg andc is the speed of light in metres per second (which then gets squared).The conversion factor is left incomplete.There are other conversion factors we use without thinking, because their value happens to be 1. For example:F = m a1 N = 1 kg * 1 m/s^2We should really writeF = [1 N s^2 / (kg m)] m abut we don’t. orF = [1 lb s^2 / slug ft] m afor mass in “slugs” and acceleration in “feet per second per second”.In the case of the “famous” equation, we should write:E = [1 N s^2 / (kg m)] m c^2which would give us an answer in N m (Newton-metres) which happens to be the unit we call Joule.Then, if we know the rate at which the matter is transformed into energy, we can find the rate of Joules per second (an output unit called Watt).....
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