A uniform electric field with a magnitude of 1150 N/C points in the negative x direction, as shown in Figure 2?

Question

A uniform electric field with a magnitude of 1150 N/C points in the negative x direction, as shown in Figure 20-21, where L = 1.2 cm.http://www.webassign.net/walker/20-21alt.gif(a) What is the difference in electric potential, ΔV = VB - VA, between points A and B?(b) What is the difference in electric potential, ΔV = VB - VC, between points B and C?(c) What is the difference in electric potential, ΔV = VC - VA, between points C and A? (d) From the information given in this problem, is it possible to determine the value of the electric potential at point A? why?

Hermina Ferry · Accepted Answer

The diagram is far from clear. However:(a) Since A and B are perpendicular to parallel field lines, ΔVAB = 0(b) I can't see L on the diagram.But if B and C are 1.2 cm = 0.012m apart, then ΔVBC = 1150 N/C * 0.012m = 13.8 Volts(c) Use the dimensions to work out the vector magnitude and direction etc.(d) No. Because no reference potentials are stated.

Hermina Ferry · Answer

the version in electric ability is with reference to the electrical powered field in accordance to delta V = - E dot L the place dot skill the dot product such that E dot L = E L cos (theta) the place E is the potential of the electrical powered field, L is the separation between the two factors, and theta is the attitude between the sphere and the separation in this diagram, cos(theta) = 4L = 0.032m, so delta V = -(-1400N/C) x 0.032m = 40 4.8V

Jakob Littel

A uniform electric field with a magnitude of 1150 N/C points in the negative x direction, as shown in Figure 2?

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