An eagle is flying horizontally at a speed of 3.00 m/s when the fishin her talons wiggles loose and falls into?

Question

An eagle is flying horizontally at a speed of 3.00 m/s when the fishin her talons wiggles loose and falls into the lake 5.00m below. calculate the velocity of the fish relative to the water when it hits the water.

Anya Stehr · Accepted Answer

Vf = √[Vi² + 2*g*y] = 10.34 m/sΘ = arccos[Vi/Vf] = 73.1° below horizontal

Anya Stehr · Answer

To determine the magnitude to the velocity of fish when it hits the water, use the following equation. v = √(Final horizontal velocity^2 + Final vertical velocity^2)The final horizontal velocity is the same as the eagle’s initial speed.v = √(9 + Final vertical velocity^2)Since we don’t know the time the fish is falling, let’s use the following equation to determine the fish’s vertical velocity when it hits the water.vf^2 = vi^2 + 2 * a * d, vi = 0, a = 9.8, d = 5 vf^2 = 2 * 9.8 * 5 = 98Let’s put this number into the equation and solve for v.v = √(9 + 98)The magnitude of the velocity is approximately 10.34 m/s. Since the question asks for the final velocity, we need to use the following equation to determine the angle with respect to the water. Use the following equation.Tan θ = Vertical/Horizontal = 3/√107The angle is approximately 16.2˚ above horizontal.

Anya Stehr · Answer

Vertical V after 5m. fall = sqrt.(2gh) = 9.9m/sec.V at water = sqrt.(9.9^2 + 3^2)10.34m/sec.Direction at water = arctan (9.9/3) = 73.14 degrees below horizontal.

Karelle Stoltenberg

An eagle is flying horizontally at a speed of 3.00 m/s when the fishin her talons wiggles loose and falls into?

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