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A

Anonymous

Nov 08, 2024

At 22 °c an excess amount of a generic metal hydroxide m(oh)2 is mixed with pure water. the resulting equilibrium solution has a

At 22 °C, an excess amount of a generic metal hydroxide, M(OH)₂, is mixed with pure water. The resulting equilibrium solution has a pH of 10.30. What is the Ksp of the metal hydroxide at 22 °C?

3 Answers

A
Anonymous

Feb 17, 2025

The balanced reaction equation:M(OH)2 ↔ M^2+ + 2(OH)^-and when the Ksp = [M^2+][OH-]^2when PH + POH = 14∴ POH = 14-10.3= 3.7 and when POH = - ㏒ [OH-] 3.7 = -㏒[OH-]∴[OH] = 2x10^-4 and when [M^2+] = 1/2[OH-]∴[M^2+] = (2x10^-4) / 2 = 0.0001 MSo, by substitution in Ksp formula:∴Ksp = (0.0001 * (2x10^-4)^2 = 4x10^-12
A
Anonymous

Dec 06, 2024

1.985 x 10⁻¹²Further explanationGiven:  At 22°C an excess amount of a generic metal hydroxide M(OH)₂ is mixed with pure water. The resulting equilibrium solution has a pH of 10.30.Question:What is the Ksp of the salt at 22°C?The Process:Step-1 Because the pH is above 7, we convert it to pOH.pOH = 14 - 10.30 Hence, the pOH value is 3.70.Step-2We use the pOH to get the Therefore, Step-3Let us write the chemical equation in equilibrium of ions.:Notice that based on comparison of the coefficients, then Step-4The Ksp expression: Let's calculate the Ksp value.Thus, the Ksp is Learn more  Write the equilibrium constant for the reaction  Calculating the pH value of weak base About electrolyte and nonelectrolyte solutions Keywords: Ksp, equilibrium, pH, pOH, metal hydroxide, M(OH)₂, pure water, the chemical equation, ions,
A
Anonymous

Dec 05, 2024

2.29x10⁻¹² is Ksp of the saltExplanation:The Ksp of the metal hydroxide is: M(OH)₂(s) ⇄ M²⁺ + 2OH⁻Ksp = [M²⁺] [OH⁻]²As you can see in the reaction, 2 moles of OH⁻ are produced per mole of M²⁺. It is possible to find [OH⁻] with pH, thus:pOH = 14- pHpOH = 14 - 10.22pOH = 3.78pOH = -log[OH⁻]1.66x10⁻⁴ = [OH⁻]And [M²⁺] is the half of [OH⁻], [M²⁺] = 8.30x10⁻⁵Replacing in Ksp formula:Ksp = [8.30x10⁻⁵] [1.66x10⁻⁴]²Ksp = 2.29x10⁻¹² is Ksp of the salt

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