Balance the following equation in acidic conditions. phases are optional. cu+no3- cu^2+ +no

Question

Please balance the following redox equation under acidic conditions. The phases are optional: 
Cu + NO3^- → Cu^2+ + NO

Cierra Lemke · Accepted Answer

This is an oxidation reduction reactionoxidation happens when the species gives out electrons.Oxidation state of the element Cu increases from 0 to +2Cu  ---> Cu²⁺ +2e --1)Reduction happens when the species gains electrons.Oxidation state of N reduces from +5 to +24H⁺ + NO₃⁻ + 3e ---> NO + 2H₂O --2)To balance the reactions, number of electrons need to be balanced. Multiply 1st reaction by 3Multiply 2nd reaction by 23Cu  ---> 3Cu²⁺ + 6e8H⁺ + 2NO₃⁻ + 6e ---> 2NO + 4H₂Oadd the 2 equations 3Cu + 8H⁺ + 2NO₃⁻ --> 3Cu²⁺ + 2NO + 4H₂Oadd 6NO₃⁻ ions to each side 3Cu + 8HNO₃ --> 3Cu(NO₃)₂ + 2NO + 4H₂Othe balanced redox reaction equation is as follows;3Cu(s) + 8HNO₃(aq) --> 3Cu(NO₃)₂ (aq)+ 2NO(g) + 4H₂O(l)

Prof. Dejah Ernser · Answer

To balance the the chemical reaction, the number of molesper element is balance is both side of the reaction and also the charge in bothsides of the reation. to balnce the reaction:S2O3 2- + Cu 2+ ---> S4O6 2- + Cu+ 2S2O3 2- + Cu 2+ ---> S4O6 2- + Cu+ + e

Anonymous · Answer

Cr^2+ + H2MoO4 + H+ → Cr^3+ + Mo + H2O Cr goes from +2 to +3 or loses one e- Mo is +6 in H2MoO4 so it goes to 0 gaining 6 e- so we must multiply Cr by 6 to balance e- 6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + H2O now we balance the spectators take O first - 4 on left then, change the right side 6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + 4H2O now we have 8 H's on the right we don't want to touch the H2MoO4 so we make H+ up to 6 for a total of 8 on the left 6Cr^2+ + H2MoO4 + 6H+ → 6Cr^3+ + Mo + 4H2O Then, It's balanced

Anonymous · Answer

I think the reaction involved here is a redox reaction in acidic conditions. To balance this type of reaction, we do as follows: Balance the O atoms in each side by adding H2O on either side.Balance H atoms in each side by adding H+.Balance the charges by adding electrons.Hope this helps.

Myrna Kuhn · Answer

If your equation is Cu+NO^- 3-->Cu^2+NO, then the answer is 2 Cu + 1 NO3{-}  → 1 Cu^{2+} + 3 NO To check if it is balance, this is the solution:2- Cu- 23- N -33- O -3

Anonymous · Answer

To balance the equation, Hydrogen ion should be added to the left of the equation and water to the right of the equation as follows:Balancing the equationIt can be noted that: ions are balanced at 18+ on left hand side and 18+ on right and side just like all the other chemical elements.

Tito Heidenreich

Balance the following equation in acidic conditions. phases are optional. cu+no3- > cu^2+ +no

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