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A

Anonymous

Oct 27, 2024

Beverly and Carl are in a race. Their graphs show the data. A graph with horizontal axis time (seconds) and vertical axis velocity

In the context of the race between Beverly and Carl, the graphs they produced illustrate their performance over time. Notably, one graph features time measured in seconds on the horizontal axis and velocity on the vertical axis. Regarding the downward component of the projectile's velocity, it is important to note that it continually increases due to the acceleration of gravity acting on the projectile throughout its flight.

4 Answers

R
Ryan Schmidt

Jan 10, 2025

C. The downward component of the projectile's velocity continually increasesExplanation:The motion of a projectile consists of two independent motions:  - A uniform motion (with constant velocity) along the horizontal direction   - A uniformly accelerated motion, with constant acceleration (equal to the acceleration of gravity) in the downward direction  Here we want to study the downward component of the projectile's velocity. Since the vertical motion is a uniformly accelerated motion, the vertical velocity is given by:whereu = 0 is the initial vertical velocity (zero since the projectile is fired horizontally) downward is the acceleration of gravityt is the timeSo the equation becomesThis means thatC. The downward component of the projectile's velocity continually increasesBecause every second, it increases by in the downward direction.Learn more about projectile motion:#LearnwithBrainly
A
Anonymous

Feb 14, 2025

Explanation:velocity of projection = vo angle of projection = θWhen the ball is at maximum height, its vertical component of velocity is zero, So it has only the horizontal component of velocity at highest point. velocity at highest point = vo Cos θThe acceleration acting on the ball is only the acceleration due to gravity which always acts vertically downward. So, teh acceleration of the ball at the highest point is g.
A
Anonymous

Jan 07, 2025

Option E is correct.There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.Explanation:Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given asR = (u² sin 2θ)/gwhereu = initial velocity of the projectile = 20 m/sθ = angle above the horizontal at which the projectile was launched = 30°g = acceleration due to gravity = 9.8 m/s² R = (30² sin 60°) ÷ 9.8R = 78.53 mSo, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.Hope this Helps!!!

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