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Sigrid O'Kon

Feb 20, 2025

Calculate the equilibrium concentration of hc2o4− in a 0.20 m solution of oxalic acid.

Calculate the equilibrium concentration of hc2o4− in a 0.20 m solution of oxalic acid.
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For the first dissociation of H2C2O4 ↔ H+ + HC2O4-, pKa = 1.23 Ka = 10^-1.23 Ka = 0.0589 Ka = [H+] [ HC2O4-] / [H2C2O4] Call [H+] = X which will also = [HC2O4-] and that [H2C2O4] = (0.2-X ) So we can write: 0.0589 = X² / (0.2-X) X² = 0.0589( 0.2 - X) X² = 0.01178 - 0.0589X X² + 0.0589X - 0.01178 = 0 Solve quadratic for X: Positive root = 0.083 The molar concentration of HC2O4- at equilibrium = 0.083M This is from yahoo. Credit to Trevor H... Show More
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Answerstrong acids and bases completely dissociate in water.this is how strong acids and bases are defined. they will ionize 100% in solution, making a non-reversible reaction... Show More
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