Calculate the number of grams of oxygen required to convert 43.0 g of glucose to CO2 and H2O?
Glucose (C6H12O6) serves as an essential energy source for the human body. The overall reaction that occurs during its metabolism can be represented by the following equation:
C6H12O6 + 6O2 → 6CO2 + 6H2O.
Given that we have 43.0 g of glucose, please calculate the number of grams of oxygen required to fully convert this amount of glucose into carbon dioxide (CO2) and water (H2O). Additionally, compute the total number of grams of carbon dioxide produced in this reaction.
2 Answers
Always start with your measured amount given. 43.0 g of glucose
43.0 g glucose *1mol glucose /180.16 g =0.24 mol glucose.
0.24 mol glucose * 6mol oxygen/ 1mol glucose (mole to mole ratio) =1.44 mol oxygen
1.44 mol oxygen * 34 grams oxygen (oxygen is diatomic) /1mol oxygen =48.96 g oxygen.
As for CO2,
1.44 mol oxygen (or any mole amount you have) * 6 mol CO2 / 6 mol O2
one to one ratio, meaning you will get 1.44 mol of oxygen to 1.44 mol CO2
1.44mol CO2 *44.01 g CO2 /1mol CO2 = 63.37 g CO2
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