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Sigrid O'Kon

Feb 20, 2025

Calculate the number of grams of oxygen required to convert 43.0 g of glucose to CO2 and H2O?

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation: C6H12O6 + 6O2 -----> 6CO2 + 6H2OCalculate the number of grams of oxygen required to convert 43.0 g of glucose to CO2 and H2O.Also compute the number of grams of CO2 produced.
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Always start with your measured amount given. 43.0 g of glucose43.0 g glucose *1mol glucose /180.16 g =0.24 mol glucose. 0.24 mol glucose * 6mol oxygen/ 1mol glucose (mole to mole ratio) =1.44 mol oxygen1.44 mol oxygen * 34 grams oxygen (oxygen is diatomic) /1mol oxygen =48.96 g oxygen. As for CO2, 1.44 mol oxygen (or any mole amount you have) * 6 mol CO2 / 6 mol O2 one to one ratio, meaning you will get 1.44 mol of oxygen to 1.44 mol CO21.44mol CO2 *44.01 g CO2 /1mol CO2 = 63.37 g CO2... Show More
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Everything you did was right except The "34 grams of Oxygen (oxygen is diatomic)" the mass remains 32g per mol... Show More
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