Can someone explain why log(500) = 3 – log(2)?
Could someone explain why log(500) equals 3 – log(2) when using base 10? I’m curious if there is a specific property or rule in logarithms that justifies this equation. Thank you!
5 Answers
log(500)
=log(1000/2) replace 500 with 1000/2
=log1000-log2 use the log property to change the fraction to a difference
=3-log2 replace log1000 with 3
The answer is already been posted.
It is because log(1000/2) is the same as log(1000)-log(2) [if you remember your properties)
Then log(1000) is 3
so it ends up
3 – log (2)
3- log2 = 3*log10 – log2
= log10^3-log2
= log1000-log2
=log1000/2
=log500
because logm -logn= logm/n dats a basic rule
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