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Johathan Wehner

Feb 20, 2025

Chemistry Homework Problem?

A piece of aluminum foil 1.00 cm square and .550 mm thick is allowed to react with bromine to form aluminum bromide.a) how many moles of aluminum were used? (density of aluminum = 2.699g/cm^3)b) how many grams of aluminum bromide form assuming that the aluminum reacts completely?Could you show your work please? Thank You
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J
Johathan Wehner

Feb 20, 2025

a)work out the volume of Al in cm^3Volume = l x b x h= 100 cm x 1.00 cm x 0.0550 cm = 0.0550 cm^3then work out the massdensity = mass / VolumeTherefore mass = density x volume= 2.699 g/cm^3 x 0.0550 cm^3= 0.148445 gmoles = mass / molar mass= 0.148445 g / 26.98 g/mol= 0.00550 molb)write a balanced equation2Al + 3Br2 ----------> 2AlBr32 moles Al react to form 2 moles AlBr3A 1 : 1 reaction ratioTherefore maximum moles AlBr3 possible = moles Al used= 0.00550 mol AlBr3 possiblemass = molar mass x molesmass AlBr3 = 266.68 g/mol x 0.00550 mol= 1.47 g (3 sig figs)... Show More
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