Find the current through the resistor b.?
I've successfully determined the current through resistor A, but I'm struggling to find the current through resistor B. I really need this information to complete the rest of the problem. Could you please explain the process? Thank you! Link to the problem for reference
1 Answers
c and d are in series, so their equivalent resistance is 10 Ohms. That 10 Ohms is in parallel with b which is 10 Ohms. So the b,c,d equivalent is 5 Ohms. And that 5 Ohms is in series with A which is 5 Ohms. So all 4 resistors have an equivalent resistance of 10 Ohms. The figure does not say what E is but the current that goes out into the network is E/10 Ohms.
At the node that is common with resistors a, b, and c; the current will divide in 2 equal parts. So the current in b is (1/2)*E/10 Ohms. The current in the c&d branch is also (1/2)*E/10 Ohms.
Ah. E=6 So E/10 Ohms = 0.6 A. (1/2)*E/10 Ohms = 0.3 A
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