Help with this one question please?

Question

In this virtual lab, you will use coffee cup calorimetry to determine the specific heat (c) of a metal. 
1) Imagine that in the lab, you record the mass of a piece of metal, denoted as m(metal) = 45.00 g. In the next step of the lab (as shown in the animation to the left), you heat the piece of metal. Play the animation and record the metal's highest temperature, T(metal). T(metal) = _____ °C (it starts at 22 °C and heats up to 83 °C).
2) In another step of this lab, you record the mass of water (m(water)) in a coffee cup as m(water) = 130.00 g. What is the initial temperature of the water, T(water1), in the coffee cup as shown to the left? T(water1) = _____ °C. 
In the next step of the lab (as shown in the animation to the left), you place the hot piece of metal into the cool water. Play the animation and record the final temperature of the water, T(water2). T(water2) = _____ °C (it starts at 22 °C and heats up to 25 °C).
With the information above and the specific heat of water, 4.184 J/(g·°C), you can calculate the specific heat (c) of the metal.

Anonymous · Accepted Answer

-(mcTf)metal= -(mcTf)water
-(45.00g x c x 61) = -(130.00g x 4.184J/(gC) x 3)
-2745 = -1631.76
(-1631.76) / (-2745) = .5944J/(gC)

Anonymous · Answer

Coffee Cup Calorimetry Lab

Anonymous · Answer

Katie is right... she just needed to be more explanatory..
45.00 x c x (83 Temperature metal final- 22 T metal initial)= 130x 4.184 j/(gC)x (25 T water final -22 T water initial)
45 x c x 61 = 130 x 4.184 x 3
2745c = 1631.76
etc...

Anonymous · Answer

I had the same question!

Anonymous · Answer

Can you please explain a little better. I have no clue what you guys are explaining.

Anonymous

Help with this one question please?

5 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions