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A

Anonymous

Feb 06, 2025

How do I determine the bond order of Mg2?

How do I determine the bond order of Mg2?

The question indicates the following molecular orbital configuration: (σ3s), (σ3s), (π3p), (π3p), and (σ3p). In other words, the bonding pattern is similar to that of the (σ2s) to (σ2p) configuration. Could someone guide me through the process of calculating the bond order for Mg2 using this information?

1 Answers

A
Anonymous

Feb 12, 2025

This is the same as a second period diatomic analogous to Be2:

MO diagram with no sp mixing (it doesn’t matter if we have sp mixing or not)

Mg [Ne] 3s^2

Mg2 = 4e⁻= 3σs(2e⁻) 3σs*(2e⁻) 3σp(0) 3πp(0e⁻) 3πp*(0e⁻) 3σp*(0e⁻)

Bond Order = ½[Σ (bonding e-) – Σ (antibonding e-)]

bo = ½[ {σs(2e⁻)} – {σs*(2e⁻)}] = 0

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