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Dr. Juanita Wolff

Feb 20, 2025

how do you solve 9x^2+21x-8=0?

i need help solving this if anyone could show me how that would be great!
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Natalie Goodwin

Feb 20, 2025

Factor the equation first.9x^2 + 21x - 8 = 0 → (3x - 1) (3x + 8) = 0Set both factors to zero: (3x - 1) = 0(3x + 8) = 0Now solve for x:(3x - 1) = 03x = 1 x = 1/3(3x + 8) = 03x = -8x = -(8/3) or - 2.6667Always plug the answers you get BACK into the equation as a check!Best of luck in your studies,~ Mitch ~.... Show More
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