how do you solve 9x^2+21x-8=0?
I need help solving the equation (9x^2 + 21x - 8 = 0). If someone could show me the steps to find the solutions, I would greatly appreciate it!
1 Answers
Factor the equation first.
9x^2 + 21x - 8 = 0 → (3x - 1) (3x + 8) = 0
Set both factors to zero:
(3x - 1) = 0
(3x + 8) = 0
Now solve for x:
(3x - 1) = 0
3x = 1
x = 1/3
(3x + 8) = 0
3x = -8
x = -(8/3) or - 2.6667
Always plug the answers you get BACK into the equation as a check!
Best of luck in your studies,
~ Mitch ~
.
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