How many oxygen atoms are in 1.30g of quartz?
How many oxygen atoms are present in 1.30 grams of quartz?
3 Answers
Pure quartz has a molecular compostion of SiO2. The mol weight of SiO2 is
2 * 16 + 28 = 60 g/mol
mols of SiO2 = 1.30 / 60 = 0.0217 mol.
Number of O2 atoms = 2 * 0.0217 * 6.022 x 10^27 = 2.61 x 10^26
Pure quartz consist of SiO2. The molecular weight of SiO2 is actually
Si= 28
O2= 32
combined this gives you a total of 60 g/mol
so you would then take 1.30g / 60 g/mol = .02167
so since there are 2 Oxygen atoms then you multiply= .02167 x 2= .04333
Then you take .04333 x 6.022 x10^23 = 2.61 x10^22
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