In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s.
When preparing to perform a slam dunk, a basketball player starts from rest and accelerates to a speed of 6.0 m/s in 1.5 seconds. Assuming the player accelerates uniformly, how can we determine the distance he runs during this time?
I’ve tried solving this problem in several ways, but I feel like I’m overcomplicating it. The answer is supposedly 4.5 meters—can someone explain how to arrive at that solution?
4 Answers
acceleration is constant. therefore, change in velocity/change in time = acceleration.acceleration = 4m/s^2now you need the equations of motion.one of them iss = ut + 1/2*a*t^2wheres= displacement (distance)u = initial velocity (initial speed)a = accelerationt = time.just plug the numbers in…s = 0*1.5 + 1/2*4*1.5^2= 4.5m
Feb 22, 2025
The equation you’re looking for is one of the equations of motion:s = (v + u)t / 2u = 0m/s (initial speed) v = 1.5m/s t = 1.5s s = ?m (distance)s = (6 + 0) x 1.5 / 2 = 4.5 metresThe equation basically says that the distance is equal to the average speed [(v+u)/2] multiplied by the time taken.
S=0.5(U+V)tS = the distance U = the initial velocity V = the final velocity t = time S = 0.5 x (0+6.0) x 1.5 = 4.5 meters
simples
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