In heating a kettle of water on an electric stove, 3.34 x 10^4 J of thermal energy was provided by the element?

Question

… of the stove. Yet, the water in the kettle gained only 5.95 X 10^2 J of thermal energy. Determine the percent of efficiency of the electric element in heating the kettle of water. Show your work

Jayce Wintheiser · Accepted Answer

Divide the energy gained by the water by the energy produced by the stove element. That will will be the fractional efficiency. Multiply by 100% to convert that to percentage. 5.95*10^2J / 3.34*10^4J = 1.78143 x 10^-2 = 0.0178 fractional efficiency 0.0178 * 100% = 1.78% This process had an efficiency of 1.78%, while the rest of the energy was lost to heating the pot itself, as well as the atmosphere (by convection) and the walls and ceiling (by radiation).

Jayce Wintheiser · Answer

Heating Kettle

Jayce Wintheiser · Answer

Even the right answers don’t have the right reason… Kettle on gas stove.  You avoid the conversion from fuel to electricity at the powerplant, and the loss in conversion from electricity to microwaves (around 50%).  But this only applies if you don’t heat a lot more water than you’re about to use.

Mr. Keeley Hilpert

In heating a kettle of water on an electric stove, 3.34 x 10^4 J of thermal energy was provided by the element?

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