In triangle ABC, a=6, b=7, c=10?

Question

To the nearest tenth of a degree, angle A = ?The area of triangle ABC to the nearest tenth is?

Jayce Wintheiser · Accepted Answer

a)With the Law of Cosines, we have: a^2 = b^2 + c^2 – 2bc*cos(A).With a = 6, b = 7, and c = 10, we have:6^2 = 7^2 + 10^2 – 2(7)(10)*cos(A)==> 36 = 49 + 100 – 140cos(A)==> -140cos(A) = -113==> cos(A) = 113/140==> A ≈ 36°.b)From here, we can find that the area is:Area = (1/2)bc*cos(A) = (1/2)(7)(10)cos(36°) ≈ 28.3 square units.I hope this helps!

Jayce Wintheiser · Answer

because of the fact the shortest edge of ABC is 24, the courting between 24 and six A’ is a million/4A consequently, because of the fact the triangle is similiar, A’B’C’ has all lengths a million/4 of the respective ABC lengths. consequently, longest part is going to be CA, at a million/4*40 = 10

Jayce Wintheiser · Answer

Umm, your quesition is confusing. Are you giving me the angle measurements or the side lengths.Since i dont know i’ll tell you the formulas you can use:-to find area. 1/2 X Base of the triangle X the height of the triangleto find degrees, you have to use SIN COS or TAN. Sin is Opposite/hypotenuse side from the angle. Cos is Adjacent/ hypotenuse and Tan is Opposite/Adjacenthope this helps a lil

Jayce Wintheiser · Answer

use the cosine ruleCos A = c^2+b^2-C^2 / 2acthis is for the areathe areas half base times the height

Jayce Wintheiser · Answer

Try the law of cosines

Mr. Keeley Hilpert

In triangle ABC, a=6, b=7, c=10?

5 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions