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A

Anonymous

Oct 29, 2024

novice skier, starting from rest, slides down a frictionless 34.0° incline whose vertical height is 124 m.?

A novice skier starts from rest and slides down a frictionless incline that is angled at 34.0° and has a vertical height of 124 meters. What is her speed when she reaches the bottom of the incline, expressed in meters per second (m/s)?

2 Answers

A
Anonymous

Dec 30, 2024

K.E = G.P.E

½mV² = mgh

½m(V)² = m(9.8)( 124sin34)

V = 36.86456395 m/s

A
Anonymous

Dec 31, 2024

As there are actually not any losses (e.g., friction), her taking off PE = mgH = a million/2 mV^2 = KE on the backside. So V = sqrt(2gH) = sqrt(2*9.8*one hundred twenty 5) = 40 9.49747468 = 40 9.5 mps. ANS. The lesson precise that's that that's particularly common as quickly as you be attentive to the physics, it fairly is the conservation of ability.

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