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physics help?! Find the box’s speed vf at 2.0s after you first started pushing on it.?

A box of mass 3.1kg slides down a rough vertical wall. The gravitational force on the box is 30N . When the box reaches a speed of 2.5m/s , you start pushing on one edge of the box at a 45∘ angle (use degrees in your calculations throughout this problem) with a constant force of magnitude Fp = 23N , as shown in figure. (Figure 1) There is now a frictional force between the box and the wall of magnitude 13N . How fast is the box sliding 2.0s after you started pushing on it? if you could show work/ what equations are used thatd be wonderful!
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Everardo Feil

Feb 20, 2025

No figure 1! I’ll assume the applied force is at 45 degrees upwards.??Original speed 2.5m/sec^2.UP component of applied force = (sin 45 x 23) = 16.263N.You then produce 13N. frictional force.Total force acting upwards = (16.263 + 13) = 29.263N. The weight of the box is (3.1 x g) = 30.38N.Net accelerating force now operating = (30.38 – 29.263) = 1.117N.The acceleration is still positive. Acceleration = (f/m) = 1.117/3.1, = 0.36m/sec^2.After 2 secs., the box has gained (at) = 0.36 x 2) = 0.72m/sec.Final speed after 2 secs = (2.5 + 0.72) = 3.22m/sec.... Show More
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