PLEASE HELP!! MAsteringPhysics What is the speed of each section (relative to Earth) after the explosion?

Question

A 885 two-stage rocket is traveling at a speed of 5.05×103 with respect to Earth when a pre-designed explosion separates the rocket into two sections of equal mass that then move at a speed of 2.50×103relative to each other along the original line of motion.(a) What is the speed of each section (relative to Earth) after the explosion? v1,v2=(b) What are the direction of each section (relative to Earth) after the explosion?ANS: BOTH AWAY FROM EARTH(c) How much energy was supplied by the explosion? [Hint: What is the change in KE as a result of the explosion?]I attempted the question and got it wrong TWICE!! PLease help me. I have three chances left but I've already lost points. I don't know how else to do the problem. Please help. Ive browsed through yahoo answers for a similar question and found a few and worked it out similarly but its still wrong.PLEASE HELP!!MY ATTEMPTED ANSWERS which were incorrectAttempt one : For (A) V1= 10100 V2=7600Attempt two: For (A) V1= 2500, 0.00913

Everardo Feil · Accepted Answer

a) Since the stages have equal mass, one stage gains half of the change in velocity and the other stage loses half of the change in velocity, orv1 = 5050m/s + 1250m/s = 6300 m/sv2 = 5050m/s - 1250m/s = 3800 m/sNote that their separation velocity = 2500 m/sb) Correct, both are still headed away from earth (v > 0)c) initial KE = ½ 885kg (5050m/s)² = m * 1.128e10 Jfinal KE = ½ (885kg/2) (6300² + 3800²)m²/s² = 1.198e10 Jsupplied energy = 6.91e8 J = 691 MJ

Mr. Durward Cummerata

PLEASE HELP!! MAsteringPhysics What is the speed of each section (relative to Earth) after the explosion?

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