Solve 9x = 27 ?????????….?

Question 1: Solve 9x=279x = 27x =27/9x = 3Question 2:(ab)^-2=(1/ab)^2=1/a^(2)b^(2)Question 3: If (-2,y) lies on the graph of y = 3x, then y =?y = 3xy = 3^(-2) y =1/3^2y =1/9Question 4: Solve 2^x =1/322^x=1/32 (since 1/32 = 1/2^5 = 2^(-5))2^x=2^-5 (if 2^x = 2^y, then x=y)x=(-5)Question 5:(-32)^(3/5)=fifth root of [(-32)^3]=fifth root of [-32768]=-8or(-32)^3/5 (no parenthesis) =(-32768)/5=-6553.6 (it’s real, but has a decimal)Question 6:2^x = 642^x = 642^x = 2^6x = 6remember that:(a) to make a power positive, get it’s reciprocalEx: (2/5)^(-3)=(5/2)^(3)=(5^3/2^3)=125/8(b) in an exponential fraction, the numerator becomes the exponent of base while the denominator will be its rootEx: 2^(2/3)=cube root of 2^2=cube root of 4Ex: (3/4)^(-2/3)=(4/3)^(2/3)=[4^(2/3)/3^(2/3)]=[cube root of 4^2/cube root of 3^2]=[cbrt {16}/cbrt {9}]=cube root of (16/9)(c) if both sides of an equation has only equal bases with only division or multiplication, you can equate its exponents. remember that in multiplication, exponents are added and in div., exp. are subtracted.Ex: 3^x=3^5x=5Ex: 3^x={(3^5)(3^2)}/3^4x={5+2}-4x=3Ex: 3^x=(3^5)+(3^2)In this case, you cannot equate the exponents automatically, here, you can use logarithm to equate x (its another big talk so don’t mind it first). 🙂just follow these rules and i’m sure you can perfect your assignments 🙂 🙂 🙂 🙂... Show More

9x=27x=3if(-2,y)y=3^xanswer 1/9 2^x = 1/32x=-5(-32)^3/5no real number 2^x = 64x=8... Show More

i basically attempt to unravel this concern : first x=3 the consequence is1 -6 10 -6 9 0 2nd x=(-one million) the consequence is one million -10 18 -fifty 4 -27 0 the 0.33 x=3 the consequence is one million -3 one million -3 0 the forth x=(3) the consequence is one million 0 one million 0 the final x=(-one million) the consequence is one million -one million 0 so the roots are (x=3)(x=3)(x=3)(x=-one million)(x=-one million)... Show More