The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.?
How much lower must the activation energy be for the hydrolysis of sucrose into glucose and fructose when catalyzed by an enzyme that increases the reaction rate by a factor of 1 million? Assume the following conditions: the uncatalyzed activation energy is 108 kJ/mol, the frequency factors for the catalyzed and uncatalyzed reactions are identical, and the temperature is 298 K.
2 Answers
This problem can be solved by using the following equation:
k = Ae^-Ea/RT
Where k = rate constant; A = arrhenius factor; Ea = Energy of activation; R = gas constant; T = Absolute temp.(K)
k1 = A e^-E1/RT
k2 = A e^-E2/RT
OR k2/k1 = e^(E1 - E2)/RT
OR ln k2/k1 = (E1 - E2)/RT
Here let k1 = k then k2 = 10^6k; E1 = 108 kJ/mol = 108000 J/mol; E2 = ?; R = 8.314 J/mol; T = 298K
Hence ln 10^6 = (108000 - E2)/(8.314x298)
Or 13.81 x 8.314 x 298 = 108000 - E2
Or 34215.27 = 108000 - E2
Or E2 = 108000 - 34215.27 = 73784.73 J/mol = 73.78 kJ/mol
hydrolysis is while water is further to break some thing into smaller products hydro - water lysis - wreck aside An O interior the sucrose probable attaches to the H of the H2O, while this occurs, the O will probable detach from the different atom that the O replaced into related to (probable a C). This leaves the OH of the H2O to attach to the unattached end of the molecule for this reason splitting it into 2 factors. One section has the OH from the H2O, the different has the H. EX: sucrose-(ho) + hoh --> sucrose-(ho)hoh --> glucose-h + fructose-oh (no longer saying that i'm useful which sugar gets which portion of the h2o, it is basically an occasion) for clarification, the (ho) is portion of the sucrose molecule, no longer a separate piece, it is basically no longer basic to place in writing applying text textile; additionally the (ho) interior the basically suited result's portion of the glucose molecule, so it is not any longer shown; the h and oh staggering off of glucose and fructose are additionally portion of the sugars, no longer basically exess products condensation might contain the removing of water, so in case you have been to place fructose and glucose back mutually to acquire sucrose, it may be a condensation because of the fact the OH from one and an H from the different might could be bumped off to confirm that them to greater wholesome back mutually, H and OH are not marvelous so as that they might come mutually to variety HOH in the past it might even bypass away the unique molecule EX: Glucose-h + fructose-oh --> glucose*h-oh*fructose--> sucrose + HOH (* shows a partial bond) woo i desire I helped! ð
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