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The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.30. What force is required …?

The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.30. What force is required to push it down a 6.0° incline and achieve a speed of 68 km/h at the end of 75 m?

1 Answers

Hello,Vo=0m/s , x=75m , V=18.8888889m/s , a=? V² = Vo² + 2ax ==> a = [V² - Vo²]/(2x) = [18.8888889² - 0²]/(2*75) = 2.3786m/s²From Newton's second law: F + mgsin(θ) - μmgcos(θ) = maF = m[a + μgcos(θ) - gsin(θ)] = 22[2.3786 + 0.39.8cos(6°) - 9.8*sin(6°)]F = 94.118N... Show More

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