The table shows the position of a cyclist. Find avg velocity?
The table below shows the position of a cyclist over time.
| Time (t in seconds) | 0 | 1 | 2 | 3 | 4 | 5 | |---------------------|-----|-----|-----|-----|-----|-----| | Position (s in meters) | 0 | 1.5 | 4.9 | 10.4 | 17.4 | 24.8 |
(a) Calculate the average velocity for each of the following time intervals:
(i) [1, 3] __ m/s
(ii) [2, 3] _ m/s
(iii) [3, 5] m/s
(iv) [3, 4] ___ m/s
(b) Estimate the instantaneous velocity when t = 3 seconds. ______ m/s
2 Answers
Find the average velocity by using the secant slope form… For instance..1ai) (f(3) – f(1))/2= (10.4 – 1.5)/2= 4.451aii) (f(3) – f(2))/(3 – 2)= 10.4 – 4.9= 5.5You try the last two parts for 1a) by yourself…1b) Take points at t = 2 and t = 4 and apply the secant slope form. You should get…m(3) ≈ (f(4) – f(2))/2= (17.4 – 4.9)/2= 12.5/2= 6.25
Good luck!
known velocity is purely the slope of a line between 2 factors. delta s / delta t. or (y2 – y1)/(x2 – x1). for 3 seconds, you’re staring at (a hundred and ten – 34) / (5 – 2) , which equals 29.3 infinitely repeating (29 and a million/3). i think of you could calculate the different 2 now which you keep in mind the thought. desire this facilitates.
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