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Jonathon Rolfson

Feb 20, 2025

Ugggh physics about velocity?

A 90 kg halfback running north with a speed of 10 m/s is tackled by a 120 kg opponent running south at 4 m/s. Compute the velocity of the two players just after the tackle.
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Bernhard White

Feb 20, 2025

Assume that at tackle time they Stick TOGETHER (don’t bounce apart) then northern (call it negative -) momentum is 90 x 10= -900 kg.m/sec and momentum south is 120 x 4 = +480 kg.m/sec. now momentum is additive and conserved so the combined mass of the two players is (-900 +480)kg. m/sec =-420 kg m.sec.so the combined bodies will move in negative direction (which is NORTH at 420/210 =2m/second.... Show More
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Bernhard White

Feb 20, 2025

conservation of momentum – m1u1+m2u2= v x (m1+m2) (90×10) +(120x-4)=v(210) v=2m/s... Show More
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