What average force is needed to accelerate a 7.00-gram pellet from rest to 125 m/s^2 over a distance of 0.800m along the barrel of a rifle?
What is the average force required to accelerate a 7.00-gram pellet from rest to a velocity of 125 m/s, given that the acceleration occurs over a distance of 0.800 meters along the barrel of a rifle?
2 Answers
Initial velocity, u = 0
Final velocity, v = 125 m/s
Distance, s = 0.8 m
Mass, m = 7 gram = (7/1000) kg
v^2 = u^2 + 2as
Or, v^2 = 2as [u = 0]
a = v^2 / (2s) = (125)^2 / (2 × 0.8)
Required force, F = ma
Put the values of m and a, then use calculator. You will get, F = 68.359375 N
Dec 18, 2024
a = V^2/2d = 125^2/1.6 = 9,766 m/sec^2
F = m*a = 9.766*7.0 = 68.36 N
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