Mastering Physics Help! A helium ion He+ emits an ultraviolet photon of wavelength 164 nm.?
A helium ion (He+) emits an ultraviolet photon with a wavelength of 164 nm.
Part A: Determine the quantum number of the ion’s initial state.
Part B: Determine the quantum number of the ion’s final state.
1 Answers
Part A:
First find the energy using the equation: E= hc/lamba. Use the wavelength given. It should be around 7.5 eV.
Using the calculated energy, use E=13.6eV (Z^2/n^2) to find the initial state (n). Z for He is 2.
Part B:
Using the energy calculated in part A and the initial state, input the values to:
E=13.6((1/n final^2) – (1/n initial^2)) to find n final
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