What is the chemical equation of strontium nitrate and sodium sulfate?

You are correct in your equation, a double replacement reaction will occur because the ions will react to form a precipitate. Sulfates will be insoluble when combined with Ca^2+, Sr^2+, Ba^2+, and Pb^2+

However, you have set up your compounds incorrectly.

It should be this:

Sr(NO3)2 (aq) + Na2SO4 (aq) → SrSO4 (s) + 2NaNO3 (aq)

Sr has a charge of 2+ and SO4 has a charge of 2-

Therefore it will be a 1:1 ratio between Sr and SO4

It will be SrSO4, not Sr(SO4)2

Also, Na has a charge of 1+ and NO3 has a charge of 1-

The ratio needs to be 1:1

The rest was correct.

The total ionic equation will be this:

Sr^2+ (aq) + 2NO3^- (aq) + 2Na^+ (aq) + SO4^2- (aq) → SrSO4 (s) + 2Na^+ (aq) + 2NO3^- (aq)

I put 2 in front of NaNO3 to balance the equation.

It would certainly be better if doing these equations was easier on Y! Answers. I often mess up, but that’s why i check my answers after i post them.

Anyway, i hope this helps.

This Site Might Help You.

RE:

What is the chemical equation of strontium nitrate and sodium sulfate?

What is the chemical equation of strontium nitrate and sodium sulfate?

strontium nitrate and sodium sulfate

Sr(NO3)2 + Na2SO4 —–> Sr(SO4)2 + Na2NO3

am i right or wrong..im not sure..

what would be the total ionic equation and net ionic equation of this…

Chemical Symbol For Strontium

Just a couple of fixes…

You wrote”

“Sr(NO3)2 + Na2SO4 —–> Sr(SO4)2 + Na2NO3 “

These are not the correct formulas for the products. Strontium sulfate is SrSO4, and sodium nitrate is NaNO3.

Mauri doesn’t mean “formal charge”. He means “oxidation number”. Strontium has an oxidation number of +2 and sodium has an oxidation number of +1. Formal charge is determined from the bonding details in a molecule. Specifically, the number of bonding electrons and lone pairs.

And JAS makes this statement, “All group I ions are soluble.” “Soluble” or “insoluble” only refer to compounds. The individual ions cannot be “insoluble”, only a compound that they might be part of.

This is a case of misinterpreting the solubility rules. For instance, it doesn’t say that Na+ is soluble, it says that sodium compounds are soluble in water. It doesn’t say that SO4= ion is insoluble, it says that only certain sulfate compounds (SrSO4, BaSO4, PbSO4 …) are insoluble.

Remember, it’s not individual ions that are soluble or insoluble, it’s compounds that are soluble or insoluble.

Finally, JAS has the correctly balanced equations, Mauri does not. Neither has done the obvious and simply add the state symbols. I require my students to include state symbols in an exercise like this.

Sr(NO3)2(aq) + Na2SO4(aq) —> SrSO4(s) + 2NaNO3(aq)

======== Follow up =========

Sorry if I sound like a old, picky chemistry teacher. That’s because I’m an old, picky chemistry teacher. Mauri has made the fixes I suggested. Now it looks much better. Thank you.

Sr(NO3)2 + Na2SO4 —> SrSO4 + 2NaNO3

You would need a solubility table to see whether or not SrSO4 is soluble or insoluble. All group I ions are soluble, so your net ionic equation would not include Na+ or NO3- . Those are referred to as spectator ions. If strontium is insoluble then:

Total ionic: Sr2+ + 2NO3- + 2Na1+ + SO42- —-> SrSO4 + 2Na+ + 2NO3-

Net ionic: Sr2+ + SO42- —-> SrSO4

You should also add states of matter, (aq) for the ions and (s) for the SrSO4 as a subscript.