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What is the equilibrium partial pressure of SO3 in the mixture?

At 900 K the following reaction has Kp = 0.345. 2 SO2(g) + O2(g) 2 SO3(g) In an equilibrium mixture the partial pressures of SO2 and O2 are 0.135 atm and 0.455 atm, respectively. What is the equilibrium partial pressure of SO3 in the mixture?
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Mina Herzog

Feb 20, 2025

2 SO2(g) + O2(g) <=====> 2 SO3(g) Kp = [SO3]^2 / [SO2]^2 [O2]0.345 = [SO3]^2 / [0.135]^2 [0.455]0.345 = [SO3]^2 / 0.00829[SO3]^2 = 0.00286 [SO3] = 0.0535 atm... Show More
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