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What is the height of the rocket above the surface of the earth at t= 10 ?

A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical acceleration of the rocket is given by ,a_y=(2.80m/s^3)t where the +y-direction is upward. a)What is the height of the rocket above the surface of the earth at t= 10 ?b)What is the speed of the rocket when it is 310m above the surface of the earth?
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2 Answers

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Sarai Dooley Jr.

Feb 20, 2025

a_y = 2.80*tthenVy = 2.80t²/2 = 1.40t²y = 1.40 t³/3So(a) y(10) = 1.40*1000/3 = 467 mWhen y = 310 m ,t³ = 3*310/1.4 = 664 s³andt = 8.72 sVy = 1.40*8.72² = 106.6 m/s... Show More
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