What is the height of the rocket above the surface of the earth at t= 10 ?
A rocket starts from rest and moves upward from the surface of the Earth. For the first 10 seconds of its motion, the vertical acceleration of the rocket is given by ( a_y = (2.80 \, \text{m/s}^3)t ), where the +y-direction is upward.
a) What is the height of the rocket above the surface of the Earth at ( t = 10 ) seconds?
b) What is the speed of the rocket when it is 310 meters above the surface of the Earth?
2 Answers
Nov 07, 2024
a_y = 2.80*t
then
Vy = 2.80t²/2 = 1.40t²
y = 1.40 t³/3
So
(a) y(10) = 1.40*1000/3 = 467 m
When y = 310 m ,
t³ = 3*310/1.4 = 664 s³
and
t = 8.72 s
Vy = 1.40*8.72² = 106.6 m/s
Related Questions
"If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what fraction of the water wo...
Have you ever noticed how the rear wheel of a bike seems to follow the front wheel closely? Why does this happen, and is...
Find the circumference of a circle with a radius of 5 inches. Please express your answer in terms of pi.
How tall is 77 inches when converted to feet?
Please identify each of the following as measurements: Length Area Volume Mass Density Time Temperature...
In circle O, ST is a diameter. What is the value of x if (2x + 8) equals one of the following options: 22.0, 25.0, 25.4,...
Today's CPUs operate at speeds measured in gigahertz rather than kilohertz. Is this statement true or false?
I have a question regarding torque in a magnetism context. I understand that the equation τ = IABsin(θ) will be relevant...
Could you please help me find the cube roots of the complex number represented in polar form as 8(cos 216° + i sin 216°)...
A 4.5 kg box slides down a 4.4 m high frictionless hill, starting from rest. It then travels across a 2.4 m wide horizon...