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Anonymous

Feb 14, 2025

What is the partial pressure of argon, PAr, in the flask?

What is the partial pressure of argon (PAr) in the flask? The flask has a volume of 1.00 L and is initially filled with 1.10 g of argon at a temperature of 25 °C. A sample of ethane vapor is subsequently added to the same flask, resulting in a total pressure of 1.350 atm.

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Anonymous

Jan 18, 2025

a) Partial pressure of argon is 0.673 atm.b) Partial pressure of ethane is 0.427 atm.Explanation:According to the ideal gas equation:' P = Pressure of the argon gas = ?V= Volume of the gas = 1.00 LT= Temperature of the gas = 25°C = 298 K       (0°C = 273 K)R= Gas constant = 0.0821 atmL/K mol n=  moles of gas = Thus the partial pressure of argon is 0.673 atm.b) According to Dalton's law, the total pressure is the sum of individual pressures.Thus partial pressure of ethane is 0.427 atm.
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Anonymous

Dec 25, 2024

Assuming ideal gas, we can solve the total number of moles in the system as:PV=nRTSolving for n,n = PV/RT = (1.2 atm)(1 L)/(0.0821 L·atm/mol·K)(25 + 273 K)n = 0.049 Now, compute for he moles of Argon knowing that its molar mass is 39.95 g/mol.Mol Ar: 1.10 g/39.95 g/nol = 0.0275 molMol fraction of Ar = 0.0275/0.049 = 0.562Thus,Partial Pressure = Total Pressure * Mol FractionPartial Pressure = (1.2 atm)(0.562) = 0.674 atm
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