What is the partial pressure of argon, PAr, in the flask?

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What is the partial pressure of argon, PAr, in the flask? A 1.00 L flask is filled with 1.10 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.350 atm .

Tiara Rutherford · Accepted Answer

a) Partial pressure of argon is 0.673 atm.b) Partial pressure of ethane is 0.427 atm.Explanation:According to the ideal gas equation:' P = Pressure of the argon gas = ?V= Volume of the gas = 1.00 LT= Temperature of the gas = 25°C = 298 K       (0°C = 273 K)R= Gas constant = 0.0821 atmL/K mol n=  moles of gas = Thus the partial pressure of argon is 0.673 atm.b) According to Dalton's law, the total pressure is the sum of individual pressures.Thus partial pressure of ethane is 0.427 atm.

Tiara Rutherford · Answer

Assuming ideal gas, we can solve the total number of moles in the system as:PV=nRTSolving for n,n = PV/RT = (1.2 atm)(1 L)/(0.0821 L·atm/mol·K)(25 + 273 K)n = 0.049 Now, compute for he moles of Argon knowing that its molar mass is 39.95 g/mol.Mol Ar: 1.10 g/39.95 g/nol = 0.0275 molMol fraction of Ar = 0.0275/0.049 = 0.562Thus,Partial Pressure = Total Pressure * Mol FractionPartial Pressure = (1.2 atm)(0.562) = 0.674 atm

Dr. Frankie Medhurst

What is the partial pressure of argon, PAr, in the flask?

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