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Bernhard White

Feb 20, 2025

what volume of 0.812 M HCl, in milliliters, is required to titrate 1.45 g of NaOH to the equivalence point? ?

I mostly understand titration problems, but I'm not sure what to do with the 1.45 grams of NaOH
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2 Answers

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Verdie O'Kon

Feb 20, 2025

the equation isHCl + NaOH ------- NaCl +H2OHCl and NaOH are in the ratio 1:1 mol of NaOH in 1.45g=1.45/40=0.03625moltherefore this is also the mol of HCl required to react with 1.45g of NaOHmol= concentration *volumevolume of HCl required=0.03625/0.812=0.0446Litres to ml0.0446*1000=44.6millilitres... Show More
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Verdie O'Kon

Feb 20, 2025

i think that for the time of a effective acid/base reaction the quantity of the acid is the comparable because of fact the quantity of the backside. Use M1V1=M2V2 (a million.500mol/liter)(0.03220 liter)= (a million.420 mol/L)(X). X is the unknown quantity. sparkling up for x. X= 0.0340 L=34.00 mL... Show More
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