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Find the cube roots of 8(cos 216° + i sin 216°).

Find the cube roots of 8(cos 216° + i sin 216°).

2 Answers

Start at k = 0, 1, 2, because there are THREE cube roots of a complex number: k = 0: 2(cos 72° + i sin 72°) k = 1: 2(cos 192° + i sin 192°) k = 2: 2(cos 312° + i sin 312°)... Show More

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