Find the current through each resistor HELPP!!?

Yes, do the resistors first. 8 and 24 ohms in parallel make 6 ohms. Then 6 ohms and 6 ohms in series make 12 ohms. Then12 ohms and 24 ohms in parallel make 8 ohms. Finally 8 ohms and 4 ohms in series make 12 ohms total resistance. 24 V/12 ohms = 2 amps total current and all of this goes through the 4 ohm resistor. There’s one answer. 2 amps across 4 ohms makes an 8 V drop across that resistor so there’s 24-8 = 16 V across the rightmost 24 ohm resistor. 16 V / 24 ohms = 2/3 amp through that resistor. That’s another answer.The remaining 2 – 2/3 = 4/3 amps all go through the center branch, and all of that goes through the 6 ohm resistor. There’s another answer.4/3 amp across 6 ohms makes an 8 V drop across the 6 ohm resisitor, leaving 16 – 8 = 8 V across the 8 and 24 ohm resistors. 8V / 8 ohms = 1 amp through the 8 ohm resistor. Another answer.Finally, 8 V / 24 ohms = 1/3 amp across the 24 ohm resistor in the middle. Check to see that the currents all add up.Sometimes you have to write out the Kirchoff’s Law equations and grind out a system of equations. Not here. Most of the time you can use Ohm’s law and the parallel+series formulas for resistance to solve a network. Learn how to do that on these simple problems, so you’ll save time and brains for the harder ones.... Show More