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Kelsie Sawayn

Feb 20, 2025

A 0.050 M solution of the weak acid HA has [H3O+] = 3.77 × 10-4 M. What is the Ka for the acid?

1 Answers

M
Madie Hilpert

Feb 20, 2025

HA <–> H^+1 + A^-1 Ka = [H+][A-]/[HA][H+] = 3.77×10^-4 Mtherefore [A-] = 3.77×10^-4 Mand [HA] = 0.050 – 3.77×10^-4 = 0.0496 MKa = (3.77×10^-4)^2 / 0.0496 = 2.87 x 10^-6Ka = 2.9×10^-6... Show More

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