A cyclist accelerates from rest at a rate of 1.00 m/s2. How fast will a point on the rim of the tire?
A cyclist accelerates from rest at a rate of 1.00 m/s². How fast will a point on the rim of the tire (diameter = 68 cm) at the top be moving after 1.1 seconds? Please note that at any moment, the lowest point on the tire is in contact with the ground and remains at rest. Can someone please guide me through the solution to this problem? I am unsure how to approach it. Thank you!
1 Answers
okay there are quite a few steps to this problem.
The equation that will solve this problem is v=2*r*w
There are steps that we need to find these.
1. to find r we will divide the diameter 68 cm by 2 to get the radius
68cm/2= 34cm
2. to find omega (w) we will use the formula w=wi+alpha*t
we need to use this formula to find alpha: alpha=a/r
alpha is 1/34.
so just plug into the formula w=wi+alpha*t
=0+(1/34)(1.1)
w =0.0323529412
so to solve the whole problem is the formula v=2*r*w
v=2*34*0.0323529412
=2.2 m/s
I hope this helps if you....
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