A cylindrical capacitor consists of a solid inner conducting core with radius 0.300 cm…?

Question

A cylindrical capacitor consists of a solid inner conducting core with a radius of 0.300 cm, which is surrounded by an outer hollow conducting tube. The two conductors are separated by air, and the length of the cylinder is 11.5 cm. The capacitance of this configuration is measured to be 37.0 pF. 
1) Calculate the outer radius of the hollow tube, denoted as r = ??? cm. 
2) When the capacitor is charged to a potential difference of 120 V, what is the charge per unit length, represented as λ = ??? C/m, on the capacitor?

Anonymous · Accepted Answer

Capacitance/unit length of a long cylinder is

C/L = (2πεrε₀) / (ln (b/a))

b is radius of outside conductor

a is radius if inside conductor

ε₀ is 8.8542e-12 F/m

εᵣ is dielectric constant (vacuum = 1)

C = 37pF = (0.115)(2π*8.85e-12) / (ln (b/a))

ln (b/a) = 0.17283

b/a = 1.189

b = 1.189×0.3 = 0.357 cm

Second half, use Q = CV to get charge and divide by 11.5 cm to get charge per cm.

.

Anonymous · Answer

For the best answers, search on this site https://shorturl.im/avsTN

I cannot conceive of such an object. “Infinitely long, radius of 2.8 cm and zero thickness???” What universe are we talking of?

Anonymous · Answer

Capacitance is C = Q/V
Q = λL
V = (λ/2πε₀) ln(r₁/r₂)

So…
C =  (2πε₀L) / ln(r₁/r₂)

r₁ is radius of outside conductor 
r₂ is radius if inside conductor 
ε₀ is 8.8542e-12 F/m = 8.85 pF

C = 37pF = 37e-12F=(0.115 m)(2π*8.85e-12 F) / ln (r₁/r₂)
 ln (r₁/r₂) = 0.17283
then convert this to exponential form
e^(0.17283) = r₁/r₂
Solver for r₁ and substitute for r₂
r₁ = 0.357 cm

Anonymous · Answer

Can anybody answer more clearly

Anonymous · Answer

q=cv

Anonymous

A cylindrical capacitor consists of a solid inner conducting core with radius 0.300 cm…?

5 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions