A cylindrical capacitor consists of a solid inner conducting core with radius 0.300 cm…?

Question

A cylindrical capacitor consists of a solid inner conducting core with radius 0.300 cm, surrounded by an outer hollow conducting tube. The two conductors are separated by air, and the length of the cylinder is 11.5 cm. The capacitance is 37.0 pF.1) Calculate the outer radius of the hollow tube. r=???? cm2)When the capacitor is charged to 120 V, what is the charge per unit length lambda on the capacitor? λ=??? C/m

Hermina Ferry · Accepted Answer

Capacitance/unit length of a long cylinder is C/L = (2πεrε₀) / (ln (b/a)) b is radius of outside conductor a is radius if inside conductor ε₀ is 8.8542e-12 F/m εᵣ is dielectric constant (vacuum = 1)C = 37pF = (0.115)(2π*8.85e-12) / (ln (b/a))ln (b/a) = 0.17283b/a = 1.189b = 1.189×0.3 = 0.357 cmSecond half, use Q = CV to get charge and divide by 11.5 cm to get charge per cm. .

Hermina Ferry · Answer

For the best answers, search on this site https://shorturl.im/avsTNI cannot conceive of such an object. “Infinitely long, radius of 2.8 cm and zero thickness???” What universe are we talking of?

Hermina Ferry · Answer

Capacitance is C = Q/VQ = λLV = (λ/2πε₀) ln(r₁/r₂)So…C = (2πε₀L) / ln(r₁/r₂)r₁ is radius of outside conductor r₂ is radius if inside conductor ε₀ is 8.8542e-12 F/m = 8.85 pFC = 37pF = 37e-12F=(0.115 m)(2π*8.85e-12 F) / ln (r₁/r₂) ln (r₁/r₂) = 0.17283then convert this to exponential forme^(0.17283) = r₁/r₂Solver for r₁ and substitute for r₂r₁ = 0.357 cm

Hermina Ferry · Answer

Can anybody answer more clearly

Hermina Ferry · Answer

q=cv

Kelsie Sawayn

A cylindrical capacitor consists of a solid inner conducting core with radius 0.300 cm…?

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