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Kelsie Sawayn

Feb 20, 2025

A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg/m2.?

If the arms are pulled in so the moment of inertia decreases to 1.80 kg/m2. What is the final angular speed in rad/s?

2 Answers

H
Hermina Ferry

Feb 20, 2025

As external torque is absent, angular momentum (L) is conserved moment of inertia with arms extended I1 = 2.25 kg/m2.angular velocity w1=5.00 rad/sFinal angular momentum L2=I2w2=2.25*5=11.25 Js moment of inertia with arms pulled I2 = 1.80 kg/m2. final angular velocity w2= ?Final angular momentum L2=I2w2 =1.80*w2 JsAs angular momentum is conserved,Initial angular momentum=Li=I1w1=final angular momentum=L2=I2w21125=180w2w2=1125/180=6.25 rad/sfinal angular speed is 6.25 rad /s... Show More
H
Hermina Ferry

Feb 20, 2025

I1W1=I2W2I1=2.25, I2=1.80 W1=5.00 W2=???so W2=2.25*5/1.8=6.25rad/sec... Show More

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