A gas is at 20°C. To what temperature must it be raised to triple the rms speed of its molecules?
I need assistance with a problem involving the behavior of gas at a specific temperature. The exercise states: "A gas is at 20°C. To what temperature must it be raised to triple the root mean square (rms) speed of its molecules?" I am puzzled, as I obtained an answer like 6.6443×10^-27, which seems far too low. However, the correct result appears to be 2364°C. Can someone help clarify this? Thank you!
1 Answers
Jan 08, 2025
Formula for RMS velocity(C) is
C=sq.rt(3RT/M)
So, C directly proportional to T in kelvin(273+20=293)
So, C1/C2=T1/T2
C2=C1XT2/T1
3C1=C1XT2/T1
3=T2/T1
T2=3XT1
T2=3×293
T2=2637k=(2637-273)=2364oC
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