A food store makes a 11-pound mixture of peanuts almonds and raisins

Question

A food store prepares an 11-pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins also cost $1.50 per pound. The mixture requires twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?

Lily O&#039;Hara · Accepted Answer

single variable solution&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;-x lbs of almonds, so 2x lbs of peanuts & (11-3x) lbs of raisins3x + 1.5*2x + 1.5(11-3x) = 211.5x = 21-1.5*11 = 4.5 , x = 3&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;-almonds: 3 lbspeanuts: 6 lbsraisins: 2 lbs&mdash;&mdash;&mdash;&mdash;&mdash;&mdash;

Anonymous · Answer

suppose the volume of peanuts:a
                               of almonds:b
                              of raisins:c
you will have systems of equations below:
a+b+c=11;1.5a+3b+1.5c=21.00;a-2b=0
solve those equations,we will have:a=6;b=3;c=2
peanuts:6 pound
almonds:3 pound
raisins:2 pounds

Anonymous · Answer

Given: 11-pound mixture of peanuts, almonds, and raisins

Cost:

peanuts – 1.5 per pound

almonds – 3 per pound

raisins – 1.5 per pound

mixture:

twice as many peanuts as almond; total cost of mixture is 21.

a + p + r = 11 lbs

a + 2a + r = 11 lbs

3a + r = 11

r = 11 – 3a

1.5(2a) + 3a + 1.5r = 21

3a + 3a + 1.5r = 21

6a + 1.5r = 21

6a + 1.5(11-3a) = 21

6a + 16.5 – 4.5a = 21

6a – 4.5a = 21 – 16.5

1.5a = 4.5

1.5a/1.5 = 4.5/1.5

a = 3

almonds = 3 lbs

peanuts = 2a = 2(3) = 6lbs

raisins = 11 – 3a = 11 – 3(3) = 11 – 9 = 2 lbs

My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Anonymous · Answer

6.5 pound of Peanuts => $ 9.75
3.25 pound of Almonds => $ 9.75
1 pound of Raisins => $ 1.50

Ms. Yasmin O'Kon IV

A food store makes a 11-pound mixture of peanuts almonds and raisins

4 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions