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A

Anonymous

Nov 26, 2024

A gas with an initial temperature of 950 C undergoes the process shown in the figure .?

A gas with an initial temperature of 950 °C undergoes the process shown in the figure. What is the final temperature (please provide your answer in Kelvin)? Additionally, how many moles of gas are present? Thank you in advance for your assistance!

1 Answers

A
Anonymous

Dec 29, 2024

Using the ideal gas law pV = nRT From your figure p = constant = 3atm and V1 =300cm^3

V2 = 100cm^3. If you take the ratio of condition 1 to 2 you get a relationship between the temperatures.

pV1 = nRT1 or nR = pV1/T1 for condition 2 nR = p*V2/T2 setting these equal

pV1/T1= pV2/T2 or T2 = T1*V2/V1 here T1 = 950+273 = 1223K And V2/V1 = 0.33333

So T2 = 1223/3 = 408K = 135degC

Now we can solve for n n = p*V/RT use either condition to get n = 3*1.013x10^5*300/10^6/(8.314*1223) = 8.97x10^-3 mol

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